a triceatops has to children. one is 3 times older than the other. Together, their age is 50 months how old are they?

1 answer:

5 0

To solve this problem, create two equations with x and y. The pieces of information that we know are that the first child is 3 times older than the second child. Therefore if we assign child #1 the variable of x and child #2 the variable of y, we could get the following equation:

3x = y

Now, we also know that together their ages equal 50 months. Therefore:

x + y = 50 (months)

So, using these two equations you can use either substitution or elimination to find the values of x and y. You would first need to rearrange the first equation to 3x - y = 0 (just moving the y to the other side).

Then, you could add the equations together as followed:

3x - y = 0
x + y = 50
___________
4x = 50
x = 12.5

And then fill that value in to one of the equations to find y.

3x = y
3(12.5) = y
y = 37.5

So, one child is 12.5 months old and the other is 37.5 months old!

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3 years ago

A score that is three standard deviations above the mean would have a z score of

tia_tia [17]

The value of z-score for a score that is three standard deviations above the mean is 3.

In this question,

A z-score measures exactly how many standard deviations a data point is above or below the mean. It allows us to calculate the probability of a score occurring within our normal distribution and enables us to compare two scores that are from different normal distributions.

Let x be the score

let μ be the mean and

let σ be the standard deviations

Now, x = μ + 3σ

The formula of z-score is

$z_{score} = \frac{x-\mu}{\sigma}$

⇒ $z_{score} = \frac{\mu + 3\sigma -\mu}{\sigma}$

⇒ $z_{score} = \frac{ 3\sigma }{\sigma}$

⇒ $z_{score} = 3$

Hence we can conclude that the value of z-score for a score that is three standard deviations above the mean is 3.

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2 years ago

ALGEBRA 1, SEMESTER 2

SIZIF [17.4K]

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

$f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}$

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is $\frac{y_2-y_1}{x_2-x_1}$ . Using what we have, we can solve it as such: