Question

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Answer 1

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Point Slope form y − y1 = m(x − x1)

Y1: -7 x1:1 slope :-2/3

Y-(-7)=-2/3(x-1)

Y+7=-2/3(x-1)

2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?

Y-(-6)=1/3(x-(-2))

Y+6=1/3(x+2)

3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)

SlopeM: =change in y/change in x

M= -1-5/-3-4

M= -6/-7

M=6/7

So now slope:6/7, point (4,5)

Y-y1=m(x-x1)

Equation in point slope

Y-5=6/7(x-4)