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3 years ago

Can anybody help me please

Mathematics

2 answers:

34kurt3 years ago

8 0

Answer:

(8, -2)

(6, -3)

Step-by-step explanation:

y = 8/2 - 6

y = 4 - 6

y = -2

(8, -2)

-3 = 1/2 x - 6

3 = 1/2 x

6 = x

(6, -3)

zavuch27 [327]3 years ago

4 0

Answer:

Step-by-step explanation:

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Solve.

miss Akunina [59]

$4(a+2) = 8 +4a\\
4a+8=8+4a\\
0=0\\ a\in\mathbb{R}\Rightarrow A$

5 0

3 years ago

Read 2 more answers

Determine where to place the decimal point in the dividend and divisor so that the quotient is between 23 and 25

timama [110]

Answer:

Place the decimal before the last digit in both number i.e. 1602.3 and 65.4

Step-by-step explanation:

We are given the numerical expression 16023÷654.

Here, we have,

Dividend = 16023

Divisor = 654

it is required that the quotient of the division to be between 23 and 25.

If we take the numbers,

1602.3 and 65.4

This gives us,

$\frac{1602.3}{65.4}=24.5$ .

Hence, placing the decimal before the last digit in both number will give the desired result.

7 0

3 years ago

Bill is making accessories for the soccer team. He uses 838.95 inches of fabric on headbands for 32 players and 3 coaches. He al

creativ13 [48]

There was 23.29 inches used on a headband for each player.

And 8.54 inches used on a wristband for each player.

To find out how much fabric for headbands and would beused for each player/person you would do

So, if you substitute the values in it is

And finally, to find how much fabric is used on a wristband for each player/person you would use the same formula.

7 0

2 years ago

Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.

vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

$cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}$

$\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}$

4 0

2 years ago

I need help with this

Nina [5.8K]

Answer:

Its 40.9!

Step-by-step explanation:

The opposite sides of angles are most of the time congruent, or the same!

Hope this helps and don't forget to follow!

5 0

2 years ago