We know that a triangle adds up to 180 degrees.
Here, 130 is a vertical angle so on the opposite side the triangle makes, it is also 130. Then we could add 130 to 25
130 + 25 = 155
Now let’s subtract this from 180.
180 - 155 = 25.
X is a supplementary angle to 25 so subtract 25 from 180.
180 - 25 = 155
X = 155.
Solution :
Let
be the unit vector in the direction parallel to the plane and let
be the component of F in the direction of
and
be the component normal to
.
Since, 


Therefore, 
From figure,

We know that the direction of
is opposite of the direction of
, so we have



The unit vector in the direction normal to the plane,
has components :


Therefore, 
From figure,

∴ 

Therefore,


Answer:
The correct simplified answer for 9a + b - 8c - 2 (a + 3b - c) would be 7a - 5b - 6c
Step-by-step explanation:
Hope this helps! Sorry if there is no explanation, I am kinda in a rush.
Answer:
D
Step-by-step explanation:
The 30-60-90 triangle has the shortest leg as x.
If there is no x you have to use the 2x or 
Final Answer: 
Steps/Reasons/Explanation:
Question: What is the solution to the linear equation
?
<u>Step 1</u>: Simplify
to
.

<u>Step 2</u>: Cancel
on both sides.

<u>Step 3</u>: Subtract
from both sides.

<u>Step 4</u>: Simplify
to
.

<u>Step 5</u>: Divide both sides by
.

~I hope I helped you :)~