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3 years ago

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Lawrence buys his friends candy in the morning for $3 a box, but forgot some of his friends, so he went back to the candy shop a

nd purchased the same candy but they had increased in price. He paid $6 a box. Let t represent the number of boxes of candy Lawrence purchased. Write an expression that represents these purchases.

1 answer:

Butoxors [25]3 years ago

7 0

3 • t + 6 • t = the amount he spent

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Sedbober [7]

Answer:

a) >
b) >
c) <
d) >

Step-by-step explanation:

a) -3 is closer to 0 so it is larger
b) A positive number is always larger than a negative
c) A positive number is always larger than a negative
d) -234 is 1 larger than -235 which makes it larger

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3 years ago

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- 5g = 20<br> How do you solve this

dezoksy [38]

Answer:

g= -4

Step-by-step explanation:

-5g = 20

<u>Divide the -5 to both sides</u>

-5g / -5 = 20/ -5

<u>both -5 cancel out and g is left alone</u>

<u>20/-5 = -4</u>

<u>g= -4</u>

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3 years ago

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Hello there ^ _ ^ <br><br> Can you help me please ? Please explain how you find the answer. Thanks!

ziro4ka [17]

It's C because for the perpendicular line, you need to construct cross points to draw it through.

- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.

8 0

4 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

$Owl= 67.14ft$

7 0

3 years ago

The gas tank of a 2013 Honda Accord holds 17.2 gallons. How many pounds of carbon dioxide are produced by burning an entire tank

cricket20 [7]

One gallon of gasoline (6.3 lbs.) produces about 20 lbs. of carbon dioxide. This may seem weird and untrue, however, most of that weight comes from the oxygen in the air. Following the math on this means that we multiply 17.2 gallons of gas by 20 lbs. of co2 per gallon of gas burned.
This gives us the answer of 344 lbs. of carbon dioxide burned per tank of gas. (From a 2013 Honda Accord)

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3 years ago