Answer:
√
30
/5
, −
√
30
/5
Step-by-step explanation:
17 one point shots and 39 two point shots were made
<em><u>Solution:</u></em>
Given that,
At a basketball game, a team made 56 successful shots
They were a combination of 1- and 2-point shots
Let "x" be the number of 1 point shots
Then, 56 - x is the number of two point shots
The team scored 95 points in all
Therefore,
1(number of 1 point shots) + 2(number of two point shots) = 95
x + 2(56 - x) = 95
x + 112 - 2x = 95
x = 112 - 95
x = 17
Then, number of two point shots = 56 - x = 56 - 17 = 39
Thus 17 one point shots and 39 two point shots were made
Answer:
14n^2.
Step-by-step explanation:
This is Arithmetic with first term a = 14 and common difference d = 28.
Sum of n terms = n/2[2a + (n-1)d]
= n/2(28 +( n -1)28]
= n/2(28 + 28n - 28)
= 14n^2
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