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2 years ago

What is the area of the triangle? 2 3 6

Mathematics

2 answers:

LiRa [457]2 years ago

8 0

Step-by-step explanation:

multiply area is base time height then divide by 2 which is

6×2=12 12÷2=6

nexus9112 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

2*3*6=12

12/2=6

formula= b*h/2

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A town has a population of 1,000 people. The population triples every 100 years. Which equation and graph show the number of yea

photoshop1234 [79]

I believe you have to add the 1,000 and 100

3 0

2 years ago

Pleas help me please i dont know what this question is

Anna71 [15]

Answer:

A = 6

B = 1

C = 14

Step-by-step explanation:

A = 25 - 19 = 6

B = 6 - 5 = 1

C = 19 - 5 = 14

give brainliest please! <3

6 0

1 year ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

2 years ago

Chen bought a 20-foot chain for $36.50. What is the unit rate of price per foot?

jasenka [17]

About 1.83. You would set up the equation like this

3 0

1 year ago

Is 7/9 an irrational number?

Mila [183]

Answer:

7/9 is a rational number

Step-by-step explanation:

x/y where x=7 and y=9 aand an reatinal number is something that is composed of an integer

3 0

2 years ago

Read 2 more answers