Question

Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750π. What is the percentage change in volume from cylinder A to cylinder B?

Answer 1

Answer:

50% change in volume

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes.

In this problem we are to find the volume of the first  cylinder and compare with the second cylinder.

Given data

Volume v =  ?

Diameter d= ?

Radius r =  $10 in$

Height h=  $5 in$

we know that the volume of a cylinder is expressed as

$volume = \pi r^{2}h$

Substituting our given data we have

$volume = \pi*10^{2}*5\\ volume= \pi *100*5\\volume= 500\pi in^{3}$

The first cylinder as a volume of $500\pi$

The change in volume is $750\pi - 500\pi = 250\pi$

percentage = $\frac{250\pi }{500\pi } *100$

$percentage=$$0.5*100= 50$%

Answer 2

Answer:

50% increase

Step-by-step explanation: