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IgorC [24]
3 years ago
9

Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750π. What is the percentage change in

volume from cylinder A to cylinder B?
Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

50% change in volume

Step-by-step explanation:

<h2>This problem bothers on the mensuration of solid shapes.</h2>

In this problem we are to find the volume of the first  cylinder and compare with the second cylinder.

Given data

Volume v =  ?

Diameter d= ?

Radius r =  10 in

Height h=  5 in

we know that the volume of a cylinder is expressed as

volume = \pi r^{2}h

Substituting our given data we have

volume = \pi*10^{2}*5\\ volume= \pi *100*5\\volume= 500\pi in^{3} \\

The first cylinder as a volume of 500\pi

The change in volume is 750\pi - 500\pi = 250\pi

percentage = \frac{250\pi }{500\pi } *100

percentage=0.5*100= 50%

Kobotan [32]3 years ago
4 0

Answer:

50% increase

Step-by-step explanation:

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