Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750π. What is the percentage change in
2 answers:
Answer:
50% change in volume
Step-by-step explanation:
<h2>This problem bothers on the mensuration of solid shapes.</h2>In this problem we are to find the volume of the first cylinder and compare with the second cylinder.
Given data
Volume v = ?
Diameter d= ?
Radius r =
Height h=
we know that the volume of a cylinder is expressed as
Substituting our given data we have
The first cylinder as a volume of
The change in volume is
percentage =
%
You might be interested in
Answer: (A) The image of JKL after a 90° counterclockwise about the origin is shown in figure 1. (B) The image of JKL after a reflection across the y-axis is shown in figure 2.
Explanation:
(A)
From the given figure it is noticed that the coordinate points are J(-4,1), K(-4,-2) and L(-3,-1).
If a shape rotate 90 degree counterclockwise about the origin, then,
Therefore, the vertex of imare are J'(-1,-4), K'(2,-4) and L'(1,-3). The graph is shown in figure (1).
(B)
If a figure reflect across the y-axis then,
Therefore, the vertex of imare are J''(4,1), K''(2,-4) and L''(3,-1). The graph is shown in figure (2).
Answer:
see explanation
Step-by-step explanation:
A
The circumference (C) of a circle is calculated as
C = πd ( d is the diameter ) , then
C = 3.14 × 8 ≈ 25.12 in
B
The circumference (C) of a circle is calculated as
C = 2πr ( r is the radius )
Here C = 94.2 , then
2πr = 94.2 ( divide both sides by 2π )
r = = 15 cm
Answer:
The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.
Step-by-step explanation:
Use the trick of transforming the given random variable one that is standard normal distributed, aka a z-score, then look up the two percentile values in z-score tables to get two equations with two unknowns.
So, let x be the variable describing the marks of a student, and
the standardized equivalent of that (mu - mean, sigma - standard deviation).
We are looking for values of mu and sigma. At this point we'd be out of luck, but, wait, we're given two bits of info: the 10% point (aka, 90th percentile) and the 20% point (can be interpreted as 100-20th percentile). For each point we can use z-score tables to look up the corresponding values of z (just search for z tables). I found:
z-score for the 10% point: z_10=1.28
z-score for the 20% point: z_20=-0.84
That gives us two equations:
and can be solved for mu and sigma (do the work on your end, I am showing my result):
The mean of the distribution is about 53.9 and standard deviation is about 16.5 marks.