Ok so
x - the smallest
The other 4 are : x+1, x+2, x+3, x+4
We know that sum is 120
So
x+x+1+x+2+x+3+x+4=120
Combine like terms
5x+10=120
Subtract 10 on both sides
5x=120-10
5x=110
Divide by 5 on both sides
X=22
The third number is x+2 = 22+2=24
8 and 5 multiply to 40 but subtract to 3.
Answer:
5:2
Step-by-step explanation:
Answer:
Your answer would be B.
Step-by-step explanation:
a^2 + 9^2 = 113^2
Solve exponents.
A^2 + 81 = 113
Subtract 81 from each side.
A^2 = 32.
Square root each side.
A = 32
Hope this helps & good luck!
Feel free to message me if you need more help! :)