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2 years ago

Find the exact values below. If applicable, click on "Undefined". cot 7pi/6

Mathematics

1 answer:

QveST [7]2 years ago

4 0

Answer:

√3

Step-by-step explanation:

We cannot solve this operation directly. Because cot7pi/6 is undefined.

We know that 1/tan= cot.

so we will first take the reciprocal of cot that is 1/tan.

So,

cot7pi/6= 1/tan 7π/6

∵7π/6 = 210 where pi=180

so cot7π/6 =1/tan210

cot7π/6 =1/1÷√3

cot7π/6 = √3

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Sammy starts with $50 in her saving account and adds $50 each week. Write an equation that Sammy can use to show how much money

victus00 [196]

Known facts:

50 dollars is the initial amount in the saving account
50 dollars is added every week into the savings account.

Variables:

x: # of weeks
y: total amount of money in savings

Set equation based on known facts and variables:

y = 50x + 50, 50x is the rate at which it grows depending on

the week and 50 is the initial amount there

Hope that helps!

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2 years ago

3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu

djverab [1.8K]

Answer:

Probability distribution for x:

$P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\$

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

So, we have this probabilty distribution for x:

$P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\$

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3 years ago

Which classification describes the following system of equations? inconsistent and dependent consistent and dependent consistent

sveta [45]

The system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have three linear equations in three variables:

x - y - z = 0 ..(1)

2x - y + 2z = 1 ..(2)

x - y + z = -2 ..(3)

From the equation (1):

$\rm x=y+z$

Plug this value in the equation (2) and (3):

$\rm 2\left(y+z\right)-y+2z=1\\\\ y+z-y+z=-2$

After solving we get:

z = -1

y = 5

Plug the above two values in equation (1) we get:

x = 4

Thus, the system of equations is consistent and independent and the solutions are x = 4, y = 5, and z = -1 option third is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

5 0

2 years ago

How do you figure this out

Ipatiy [6.2K]

$4 \times 8 = {32}^{2} \\ 3 \times 3 = {9 }^{2} \\ {32 + 9 = 41}^{2}$

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3 years ago

Read 2 more answers

A square of side length s lies in a plane perpendicular to a line L. One vertex of the square lies on L. As this square moves a

user100 [1]

Answer:

Part (A) The required volume of the column is $s^2h$ .

Part (B) The volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

Step-by-step explanation:

Consider the provided information.

It is given that the we have a square with side length "s" lies in a plane perpendicular to a line L.

Also One vertex of the square lies on L.

Part (A)

Suppose there is a square piece of a paper which is attached with a wire through one corner. As you blow it up it spins around on the wire.

This square moves a distance h along L, and generate a corkscrew-like column with square.

The cross section will remain the same.

So the cross section area of original column and the cross section area of twisted column at each point will be the same.

The volume of the column is the area of square times the height.

This can be written as:

$s^2h$

Hence, the required volume of the column is $s^2h$ .

Part (B) What will the volume be if the square turns twice instead of once?

If the square turns twice instead of once then the volume will remains the same but divide the volume into two equal part.

$s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$

Hence, the volume be $s^2h=\frac{s^2h}{2}+\frac{s^2h}{2}$ .

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3 years ago