Find the exact values below. If applicable, click on "Undefined". cot 7pi/6

Mathematics

1 answer:

QveST [7]2 years ago

4 0

Answer:

√3

Step-by-step explanation:

We cannot solve this operation directly. Because cot7pi/6 is undefined.

We know that 1/tan= cot.

so we will first take the reciprocal of cot that is 1/tan.

So,

cot7pi/6= 1/tan 7π/6

∵7π/6 = 210 where pi=180

so cot7π/6 =1/tan210

cot7π/6 =1/1÷√3

cot7π/6 = √3

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Can somebody help me please

vesna_86 [32]

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Answer:

3n+6 (n = smallest)
3n (n = middle)

Step-by-step explanation:

The usual method for doing this is to let n represent the smallest one. Then the three integers are ...

n, n+2, and n+4

and their sum is ...

(n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)

_____

Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:

(n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)

4 0

3 years ago

Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4

lana66690 [7]

$\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}$