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Montano1993 [528]
3 years ago
9

You randomly draw a marble from a bag of marbles that contains 77 blue marbles, 22 green marbles, and 11 red marble.

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0
ANSWER

P( \bar B)= \frac{3}{10}

EXPLANATION

The number of blue marbles is

n(B)=77

The number of Green marbles is

n(G)=22

The number of red marbles is

n(R)=11

The total number of marbles is

n(S)=110


The probability of picking a blue marble is

P(B)= \frac{n(B)}{n(S)}



P(B)= \frac{77}{110}


P(B)= \frac{7}{10}


The probability of not selecting a blue marble is


P( \bar B)= 1 - P(B).



P( \bar B)= 1 -  \frac{7}{10}


P( \bar B)=  \frac{3}{10}
shepuryov [24]3 years ago
6 0

Answer: \dfrac{3}{10}

Step-by-step explanation:

Given: The number of blue marbles = 77

The total number of blue marbles = 77+22+11=110

Now, the probability of choosing a blue marble is given by :-

\text{P( draw a blue)}=\dfrac{\text{Number of blue marbles}}{\text{ Total number of marbles}}\\\\\Rightarrow\ \text{P(draw a blue)}=\dfrac{77}{110}=\dfrac{7}{10}

Now, the probability of not choosing a blue marble is given by :-

\text{P(not draw a blue)}=1-\text{P( draw a blue)}\\\\\Rightarrow\ \text{P(not draw a blue)}= 1-\dfrac{7}{10}\\\\\Rightarrow\ \text{P(not draw a blue)}=\dfrac{3}{10}

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