Question

You randomly draw a marble from a bag of marbles that contains 77 blue marbles, 22 green marbles, and 11 red marble.

Answer 1

ANSWER

$P( \bar B)= \frac{3}{10}$

EXPLANATION

The number of blue marbles is

n(B)=77

The number of Green marbles is

n(G)=22

The number of red marbles is

n(R)=11

The total number of marbles is

n(S)=110


The probability of picking a blue marble is

$P(B)= \frac{n(B)}{n(S)}$



$P(B)= \frac{77}{110}$


$P(B)= \frac{7}{10}$


The probability of not selecting a blue marble is


$P( \bar B)= 1 - P(B).$



$P( \bar B)= 1 - \frac{7}{10}$


$P( \bar B)= \frac{3}{10}$

Answer 2

Answer: $\dfrac{3}{10}$

Step-by-step explanation:

Given: The number of blue marbles = 77

The total number of blue marbles = $77+22+11=110$

Now, the probability of choosing a blue marble is given by :-

$\text{P( draw a blue)}=\dfrac{\text{Number of blue marbles}}{\text{ Total number of marbles}}\\\\\Rightarrow\ \text{P(draw a blue)}=\dfrac{77}{110}=\dfrac{7}{10}$

Now, the probability of not choosing a blue marble is given by :-

$\text{P(not draw a blue)}=1-\text{P( draw a blue)}\\\\\Rightarrow\ \text{P(not draw a blue)}= 1-\dfrac{7}{10}\\\\\Rightarrow\ \text{P(not draw a blue)}=\dfrac{3}{10}$