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4 years ago

I’m confused on how to do this

Mathematics

1 answer:

vladimir2022 [97]4 years ago

3 0

Answer:

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

Step-by-step explanation:

Ok to decide if a point is on a line you plug it in. If you get the same thing on both sides, then that point is on that line. If you don't get the same thing on both sides, then that point is not on that line.

Test (6,6) for -5x+6y=-23.

(x,y)=(6,6) gives us

-5x+6y=-23

-5(6)+6(6)=-23

-30+36=-23

6=-23

So (6,6) is not on -5x+6y=-23.

Test (6,6) for y=-4x+30

(x,y)=(6,6) give us

y=-4x+30

6=-4(6)+30

6=-24+30

6=6

So (6,6) is on y=-4x+30.

Test (3,4) for -5x+6y=-23.

(x,y)=(3,4) gives us

-5x+6y=-23

-5(3)+6(4)=-23

-15+24=-23

9=-23

So (3,4) is not on -5x+6y=-23.

Test (3,4) for y=-4x+30.

(x,y)=(3,4) gives us

y=-4x+30

4=-4(3)+30

4=-12+30

4=18

So (3,4) is not on y=-4x+30.

Test (7,2) for -5x+6y=-23.

(x,y)=(7,2) gives us

-5x+6y=-23

-5(7)+6(2)=-23

-35+12=-23

-23=-23

So (7,2) is on -5x+6u=-23.

Test (7,2) for y=-4x+30.

(x,y)=(7,2) gives us

y=-4x+30

2=-4(7)+30

2=-28+30

2=2

So (7,2) is on y=-4x+30

(x,y) Line 1 Line 2 Both Neither

(6,6) *

(3,4) *

(7,2) *

(6,6) only goes with Line 2

(3,4) goes with neither

(7,2) goes with both

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Since b is a straight line and is transversed by line m and we are given m∠6 = 128°, we can find m∠5, which is 180 - m∠6, giving us 52° for ∠5.

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