Please help me! Thank you!

Find the slope of -10x + 2y = 8 using slope intercept form

Elodia [21]

Answer:

you subtracted 2y from both sides to each side getting 2y = 10x +8

Step-by-step explanation

8 0

3 years ago

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Point O is at a distance named K from the line D. What should be the value of K if we want to find three points that their dista

Keith_Richards [23]

Answer:

the answer is number 3)2

Step-by-step explanation:

subtract the both

7 0

3 years ago

Simplify this problem::<br> -6x + 3 3/4 + 14x - 3.25

Lynna [10]

Answer:

8x + 1/2 or 8x + 0.5

Step-by-step explanation:

-6x + 3 3/4 + 14x - 3.25

u can either convert the fraction to a decimal or convert the decimal into a fraction, i'm going to do the latter

-6x + 3 3/4 + 14x - 3 1/4

rearrange to make it easier, don't need to do this i'm just doing this for the sake of it

-6x + 14x + 3 3/4 - 3 1/4

8x + 2/4, simplify this

8x + 1/2

The decimal way if u want:

-6x + 3 3/4 + 14x - 3.25

-6x + 3.75 + 14x - 3.25

-6x + 14x + 3.75 - 3.25

8x + 0.5

6 0

3 years ago

What is the median of the following set? {5, 2, 9, 7, 4}<br><br> A: 5<br> B: 7<br> C: 8<br> D:9

hram777 [196]

A. 5

(2,4,5,7,9)

5 is in the middle between 4 and 7.

8 0

3 years ago

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Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$

$\implies -x+3-(x^2-9)=\dfrac{45}{4}$

$\implies -x+3-x^2+9=\dfrac{45}{4}$

$\implies -x^2-x+\dfrac{3}{4}=0$

$\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)$

$\implies 4x^2+4x-3=0$

$\implies 4x^2+6x-2x-3=0$

$\implies 2x(2x+3)-1(2x+3)=0$

$\implies (2x-1)(2x+3)=0$

Apply the zero-product property:

$\implies (2x-1)=0 \implies x=\dfrac{1}{2}$

$\implies (2x+3)=0 \implies x=-\dfrac{3}{2}$

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

$\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}$

Therefore, OM = ³/₂ units.

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

8 0

1 year ago

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