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Nesterboy [21]
3 years ago
12

Solve the equation for the variable v. D=2zv

Mathematics
2 answers:
user100 [1]3 years ago
6 0
Divide. v= d/2z . Solve For v By Simplifying Both Sides Of The Equation, Then Isolate The Variable .
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Arlecino [84]3 years ago
4 0
Unless this is some perplexed kind of math, how can you solve the variables when there is only one number to go from?
Is there a 'not enough information' answer choice
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Can someone just explain to me how to do this please
Dmitrij [34]

Answer: -7.5

Step-by-step explanation:

area = 1/2bh.

area = 1/2(x+6)(5)

area = x/2 + 15

area = x/2 = -15

area = x = -7.5

area = -7.5

5 0
3 years ago
34 123 006 expanded form
ololo11 [35]
Thirty four million one hundred twenty three thousand six
3 0
3 years ago
When you solve a square root problem, can you just divide it by 2? for example in this picture can you do 25 divided by 2?
user100 [1]

Answer:

No

Step-by-step explanation:

When you square a number, you chose a number and multiplying itself. If you did the square root of 25, you would get 5. However if you divided 25 by 2, you would get 12.5 which is NOT the square root.

7 0
3 years ago
Read 2 more answers
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
1 year ago
23854 miles rounded to the nearest hundred mile
erica [24]
This would equal about 23,900
i hope this helps you.
5 0
3 years ago
Read 2 more answers
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