We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
Answer:
The first choice
Step-by-step explanation:
Multiplyil by 6 to get 4y - 1 =21
Answer: [-11,4]
Step-by-step explanation:
yes in brackets
Answer:
I understand there is a typo, so Belly and Billy are the same person. His age is represented as B, and Suzy's as S.
S = 19
B = 9
Step-by-step explanation:
Suzy is ten years older than Belly:
(1) S = B + 10
the next year she will be twice as old as Billy
(2) S + 1 = 2 (B + 1)
solving the system of equation (1) and (2):
Making (2) - (1):
1 = 2 (B + 1) - B - 10 => 1 = 2 B + 2 - B - 10 => 1 = B - 8 => B = 9
replacing in (1) S = 19