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Temka [501]
2 years ago
12

What is the product of f(3) and g(–4)? f(x) = 6x + 3 g(x) = 3x – 2 HELP!!

Mathematics
2 answers:
melomori [17]2 years ago
4 0

Answer:

f(3)=21

g(-4)=-14

Step-by-step explanation:

Lerok [7]2 years ago
4 0

Answer:

Step-by-step explanation:

f(x) = 6x + 3

f(3) =6*3 +3

f(3) = 18 + 3

f(3) = 21

g(x) = 3x - 2

g(-4) = 3*-4 - 2

g(-4) = - 14

f(3)*f(-4) = 21 * -14= -294

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What is the sine value of pi over 6?
loris [4]
The value of sin (pi/6) is 1/2
8 0
3 years ago
Determine the rate of change of f , f(x)= 6x-5
vagabundo [1.1K]

Answer:

6

Step-by-step explanation:

the rate of change is given by the slope of the line

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

f(x) = 6x - 5 is in this form

with slope m = 6 ← rate of change



5 0
3 years ago
Read 2 more answers
On a bicycle trail, the city is painting arrows like the one shown below: Upper pointing arrow with height of 11 and length of 9
Studentka2010 [4]

The image of the arrow is missing, so i have attached it.

Answer:

A_t = 69.5 cm²

Step-by-step explanation:

In a second image attached, I have divided the arrow into triangle and rectangle.

From the second image,

A1 is area of triangle while A2 is area of rectangle

Area of triangle is; A1 = ½bh

Our triangle base is given as 9 cm.

To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.

Thus; height of triangle; h = 11 - 8 = 3cm

Thus;

A1 = ½ × 9 × 3

A1 = 13.5 cm²

Formula for area of rectangle is;

A2 = length × breadth

A2 = 8 × 7

A2 = 56 cm²

Thus, total area of arrow is;

A_t = A1 + A2 = 13.5 + 56

A_t = 69.5 cm²

8 0
2 years ago
PLEASE HELP!!
Elena-2011 [213]
For this case we have the following equation:
 S = 0.159 + 0.118logD
 Substituting S = 0.2 we have:
 0.2 = 0.159 + 0.118logD
 From here, we clear the value of D.
 We have then:
 0.2 - 0.159 = 0.118logD
 logD = (0.2 - 0.159) / (0.118)
 logD = 0.347457627
 10 ^ (logD) = 10 ^ 0.347457627
 D = 10 ^ (0.347457627)
 D = 2.23 mm
 Answer:
 
The average diameter, D, of the sand particles for a beach is:
 
D = 2.23 mm
5 0
3 years ago
Just read and answer me
lord [1]

Answer:

the picture isnt showing up on mines

8 0
3 years ago
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