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3 years ago

What is this? Please help

Mathematics

2 answers:

Alina [70]3 years ago

4 0

Answer:

Step-by-step explanation:

The centroid is the point where the 3 medians meet. In the diagram, the centroid is M. A median is a line that joins the midpoint of the side opposite the angle opposite the midpoint. RC is the median of PQ. You might have to read this a couple of times to have it make sense.

To find RM, you have to realize that the centroid cuts the median line in a ratio of 1:2.

In this problem, you are given more information than you need. The median containing RM is RC. If CM is 7, RM will be twice as long which is 14.

CM = 7

RM = 2*7 = 14

Oksana_A [137]3 years ago

3 0

Answer:

centriod

Step-by-step explanation:

of triiangle

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Help with this question, please!

uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0

2 years ago

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

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4 0

2 years ago

3х2 – 10x+7<br> Factor each trinomial

Archy [21]

Answer:

324

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A model car is 8 inches long and 5.2

Sphinxa [80]

Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.

7 0

2 years ago

Which property justifies this question -5 x 12 = 12 x -5

cluponka [151]

Answer:

Commutative Property of Multiplication

Step-by-step explanation:

Commutative Property of Multiplication is the switching of the order first factor (multiplicand) and the second factor (multiplier), which does not change the product. For example, 4 × 5 = 5 × 4

-5 × 12 = -60

12 × -5 = -60

8 0

2 years ago