After 4 new students joined a class, the class had 32 students.

Find the distance and midpoint for the points (5,5) and (1,2).

nikklg [1K]

Answer: wtfffff

Step-by-step explanation:

4 0

3 years ago

Help againnn i hate matg

ser-zykov [4K]

Hello User!

Correction "Math"

Answer: 12 4/7

6 0

3 years ago

PLEASE HELP!

Degger [83]

Answer:

Perimeter = 21.58 units

Step-by-step explanation:

Perimeter of a polygon = Sum of measures of all sides of the polygon

Perimeter of the quadrilateral LEAP = PL + AE + EL + LP

= 4.47 + 4.47 + 6.32 + 6.32

= 21.58 units

[If the distances between two point are not given, use the formula to calculate the distance between two points $(x_1, y_1)$ and $(x_2,y_2)$

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ ]

7 0

3 years ago

7.Find the lengths of the missing sides in the triangle. If your answer is not an integer, leave it in simplest radical form. Th

Fed [463]

Here a right angled triangle given. one angle with measure $45^o$ given. The three sides of the triangle given 4, x, y.

We have to find, the sides which is opposite, adjacent and hypotenuse here.

We know that the side opposite to right angle is always hypotenuse. So, hypotenuyse = y.

The side adjacent to the given angle $45^o$ is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is $sin(x) =\frac{Opposite}{Hypotenuse} , cos(x) =\frac{Adjacent}{Hypotenuse} , tan(x) =\frac{Opposite}{Adjacent}$ , where x is the angle given.

To get x, we will use tan. So we will get,

$tan(45^o) = \frac{4}{x}$

We know the value of $tan(45^o) = 1$ . By substituting the value we will get,

$1 =\frac{4}{x}$

To find x, we have to move x here to the left side by multiplying it to both sides. We will get,

$(1)(x) = (\frac{4}{x}) (x)$

$x = 4$

So we have got the value of x here.

Now to find y, we will use the trigonometric function sine.

$sin(45^o) =\frac{4}{y}$

we know the value of $sin(45^o) =\frac{\sqrt{2}}{2}$

By substituting the value we will get,

$\frac{\sqrt{2}}{2} = \frac{4}{y}$

By cross multiplying we will get,

$(\sqrt{2}) (y) = (4)(2)$

$\sqrt{2}y = 8$

We will get y by dividing both sides by $\sqrt{2}$ , we will get,

$\frac{\sqrt{2}y}{\sqrt{2}} =\frac{8}{\sqrt{2} }$

$y =\frac{8}{\sqrt{2} }$

Now we will rationalize the denominator by multiplying $\sqrt{2}$ to the top and bottom.

$y =\frac{8\sqrt{2}}{(\sqrt{2})(\sqrt{2})}$

$y =\frac{8\sqrt{2}}{2}$

$y = 4\sqrt{2}$

So we have got the required values of x and y.

8 0

3 years ago

Read 2 more answers

HELP PLZ DUR 11;59 plz help me

Norma-Jean [14]

Answer:

Base = 10 cm

Height = 60 cm

Step-by-step explanation:

The formula for the area of a triangle is $area=\frac{1}{2} *b*h$ , where b is the length of the base of the triangle, and h is the length of the height of the triangle.

We know the area is 300, and since the height of the triangle is 6 times its base, we know that $h=6*b$ . We can plug in these values into our formula for the area of a triangle, which gives us the following equation to solve:

$300=\frac{1}{2} *b*(6*b)$

$3b^2=300$

$b=\sqrt{100} =10$

The base of the triangle is 10 centimeters.

Now that we know the base of the triangle, we can plug its value in to the original formula to solve for the height of the triangle, which gives us the following equation:

$300=\frac{1}{2} *10*h$

$5h=300$

$h=60$

The height of the triangle is 60 centimeters.

5 0

3 years ago