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svet-max [94.6K]
3 years ago
9

Create an equivalent system of these equations and test your solution x + y = 1 x 3y =9

Mathematics
2 answers:
ad-work [718]3 years ago
4 0
An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides


assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent



ok, solve initial

x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation


-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8

-4y=8
divide both sides by -4
y=-2

sub back
x+y=1
x-2=1
add 2
x=3


x=3
y=-2
(3,-2)

if we test it in other one

2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep

2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep


solution is (3,-2)
Nuetrik [128]3 years ago
3 0
Equivalent system is the same set of eqns n has the same solution

so for x + y = 1 and x + 3y = 9

an equivalent system can be created by multiplying everything by 3

3x + 3y = 3 and 3x + 9y = 27

solving by substracting one from the other

9y - 3y = 27 - 3

6y = 24

y = 4

x = 1 - y = 1 - 4

= -3

substituting (-3,4) back into

<span>x + y = 1 and x + 3y =9

-3 + 4 = 1 and -3 + 3*4 = 9

so the solutions are good</span>
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Answer:

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Answer:

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the answer is option c (0.84)

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AfilCa [17]

Answer:

Therefore the value of x is

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Step-by-step explanation:

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x^{2}+20=2x which is

x^{2}-2x+20=0

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x = ? using Quadratic Formula

Solution:

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x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

On Comparing with above we get

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