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Archy [21]
3 years ago
10

Work done by conservative forces is independent of the path

Physics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

True

Explanation:

Work done can be defined by the formula,

W=fdcos\theta

It is depend on the displacement d which is the vector quantity and it is the shortest distance between the two points.

The property of the conservative force is that it is only depend on the initial and the final points and does not depend which path is taken by the object.

For example potential energy due to the force of gravity is conservative now consider the point of height h then drop the ball directly to the ground or through a ramp then the potential energy will remain same that is mgh because it depend on the height not on the path taken by the object.

Therefore, conservative forces are path independent.

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A current-carrying wire oriented north-south and laid over a compass deflects the compass 8° to the east. What is the magnitude
zhenek [66]

2.8 \times 10^{-6}\ T is the magnitude of the magnetic field made by the current

<u>Explanation:</u>

Given data:

\theta=8^{\circ}

Magnetic field of earth, B_{\text {earth}}=2 \times 10^{-5}\ \text {tesla}

We need to find the magnetic field of wire, B_{\text {wire }}

The compass needle moves toward a direction of magnetic field. The current in wire makes a magnetic field in available space where the compass is on the ground. The vector sum of the Earth's magnetic field and the wire's magnetic field represents the net magnetic field, as shown in the attached drawing, expressing the angle:

                   \tan \theta=\frac{B_{\text {wire}}}{B_{\text {earth}}}

By substituting the given values, we get

                  B_{\text {wire}}=\tan \theta \times B_{\text {earth}}=\tan 8^{\circ} \times 2 \times 10^{-5}=0.1405 \times 2 \times 10^{-5}

                  B_{\text {wire}}=0.28 \times 10^{-5}=2.8 \times 10^{-6}\ T

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3 years ago
A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.180 m2. The coil is now stretched to hav
butalik [34]

Answer:

Explanation:

Given that,

Number of turns of coil

N = 50 turns

Initial area of plane

A1 = 0.18 m²

The coil it stretch to a no area in time t = 0.1s

No area implies that the final area is 0, A2 = 0 m²

Constant magnetic field strength

B = 1.51 T

EMF?

EMF is given as

Using far away Lenz law

ε = —N• dΦ/dt

Where Φ = BA

Then,

ε = —N• d(BA)/dt

Since B is constant,

ε = —N•B dA/dt

ε = —N•B (∆A/∆t)

ε = —N•B(A2—A1)/(t2-t1)

ε = —50 × 1.51 (0—0.18)/(0.1—0)

ε =—75.5 × —0.18 / 0.1

ε = 135.9 V

The induced EMF is 135.9V

Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.

Since the area lines in the plane, then the induced emf will be out of the page

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