Answer:
3 m/s
Explanation:
Parameters given:
Mass of first bowling pin, m = 1.7 kg
Initial velocity of first bowling pin, u = 3.8 m/s
Final velocity of first bowling pin, v = 0.8 m/s
Mass of second bowling pin, M = 1.7 kg
Initial velocity of second bowling pin, U = 0 m/s
Let the final velocity of the second bowling pin be V
Using the principle of conservation of momentum:
Total initial momentum = Total final momentum
m*u + M*U = m*v + M*V
(1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)
6.46 = 1.36 + 1.7V
1.7V = 5.1
V = 5.1/1.7 = 3 m/s
The potential difference across the parallel plate capacitor is 2.26 millivolts
<h3>Capacitance of a parallel plate capacitor</h3>
The capacitance of the parallel plate capacitor is given by C = ε₀A/d where
- ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m,
- A = area of plates and
- d = distance between plates = 4.0 mm = 4.0 × 10⁻³ m.
<h3>Charge on plates</h3>
Also, the surface charge on the capacitor Q = σA where
- σ = charge density = 5.0 pC/m² = 5.0 × 10⁻¹² C/m² and
- a = area of plates.
<h3>
The potential difference across the parallel plate capacitor</h3>
The potential difference across the parallel plate capacitor is V = Q/C
= σA ÷ ε₀A/d
= σd/ε₀
Substituting the values of the variables into the equation, we have
V = σd/ε₀
V = 5.0 × 10⁻¹² C/m² × 4.0 × 10⁻³ m/8.854 × 10⁻¹² F/m
V = 20.0 C/m × 10⁻³/8.854 F/m
V = 2.26 × 10⁻³ Volts
V = 2.26 millivolts
So, the potential difference across the parallel plate capacitor is 2.26 millivolts
Learn more about potential difference across parallel plate capacitor here:
brainly.com/question/12993474
Answer:
A=z+n
A=20+20
A=40
Explanation:
Not sure if I'm correct but I was taught that mass number is calculated by A=z+n where A is the mass number, z is the proton number and n is the number of neutrons.
(0.5)×(0squared)×(3)=(1.5j)
