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KengaRu [80]
3 years ago
15

How do you do this problem?? I'm very confused

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
You have to multiply by the complex conjugate so that you can clear the radical from the denominator. Once you do the multiplication simplify the radical. There's still a common factor in -54, -18, & 75 so divide all those by 3.

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a rhombus as an area of 72 ft and the product of the diagonals is 144. What is the length of each diagonal?
SashulF [63]

A = (1/2)(x)(y)

Let x = diagonal 1

Let y = diagonal 2

The product of xy = 144.

This means that x = 12 and y = 12.

So, 12 • 12 = 144

Each diagonal is 12 feet.

Prove:

72 feet = (1/2)(12)(12) feet

72 feet = (1/2)(144) feet

72 feet = 72 feet

6 0
3 years ago
Simplify.
yKpoI14uk [10]
(-5p^4z^6u)^3

= (-5)^3p^{4 \times 3}z^{6 \times 3} u^3

= -125p^{12}z^{18} u^3

---------------------------------------------------------------------------------------------------
\text {Answer = } -125p^{12}z^{18} u^3 \text { (Answer C) }
---------------------------------------------------------------------------------------------------

3 0
3 years ago
Read 2 more answers
Can anyone help me with this question​
Lina20 [59]

Answer:

78

idont know

5 0
2 years ago
The product of 2, and a number increased by 7, is -36
vodka [1.7K]

Here is the equation you should use.

2(x+7) = -36

4 0
3 years ago
Find a vector equation and parametric equations for the line through the point (1,0,6) and perpendicular to the plane x+3y+z=5.
tester [92]

The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.

Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:

(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)

This is the vector equation; getting the parametric form is just a matter of delineating

<em>x</em>(<em>t</em>) = 1 + <em>t</em>

<em>y</em>(<em>t</em>) = 3<em>t</em>

<em>z</em>(<em>t</em>) = 6 + <em>t</em>

5 0
3 years ago
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