Answer:
The weight of square is 8 grams.
Step-by-step explanation:
Given that,
The weight of the circle = 2 grams
The weight of the triangle = 4 grams
We need to find the weight of the square. Let the weight of each square is w.
On LHS, 2 circles and 4 squares are there.
On RHS, 2 squares, 4 triangles and 2 circles are there.
For a balanced position,
Weight on LHS = Weight on RHS
2(2)+4(w) = 2(w) + 4(4) +2(2)
4 + 4w = 2w +16 +4
4w-2w = 20-4
2w = 16
w = 8
So, weight of square is 8 grams.
<span>1/(4p)(x-h)^2+k=0
</span><span>1/(4p)(x-h)^2 = -k
</span>
<span>k(4p)(x-h)^2+1=0
4kp (x^2 - 2xh + h^2) + 1 = 0
4kp x^2 - 8kph x + 4kph^2+1 = 0
D = (-8kph)^2 - 4(4kp)(4kph^2+1) = 64(kph)^2 - 64(kph)^2 - 16kp
D = -16kp < 0
SO discriminant is always less than 0
</span>
Do you have answer options for this question?
Answer:
-3x+16
Step-by-step explanation: