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Oduvanchick [21]
3 years ago
8

If you roll six sided dice what are the odds of rolling doubles

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer: 16.7%

There are 6 ways we can roll doubles out of a possible 36 rolls (6 x 6), for a probability of 6/36, or 1/6, on any roll of two fair dice. So you have a 16.7% probability of rolling doubles with 2 fair six-sided dice.

Second Answer : 6/36

Out of the 6^2 = 36 outcomes, there is only 6 that are doubles (double 1,double 2,… double 6). Therefore the probability is 6/36 i 1/6.

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A flower shop sells tulips and roses. The price of each tulip is the same and the price of each roses the same. One customer bou
Talja [164]

Answer: it cost a customer $7.25 to buy five tulips and $10.5 to buy six roses.

Step-by-step explanation:

Let x represent the cost of 1 tulip.

Let y represent the cost of 1 rose.

The price of each tulip is the same and the price of each roses the same. One customer bought seven tulips and nine roses for $25.90. This means that

7x + 9y = 25.9 - - - - - - - - - - - - - - 1

Another customer bought for four tulips and eight roses for $19.80. This means that

4x + 8y = 19.8- - - - - - - - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 7, it becomes

28x + 36y = 103.6

28x + 56y = 138.6

Subtracting, it becomes

- 20y = - 35

y = - 35/ - 20

y = 1.75

Substituting y = 1.75 into equation 2, it becomes

4x + 8 × 1.75 = 19.8

4x + 14 = 19.8

4x = 19.8 - 14 = 5.8

x = 5.8/4

x = 1.45

The cost of 5 tulips would be

1.45 × 5 = $7.25

The cost of 6 roses would be

1.75 × 6 = $10.5

7 0
3 years ago
What is the slope of the line y = 8?
bagirrra123 [75]

Answer:

the slope of the line y=8 is 0

Step-by-step explanation:

0

3 0
3 years ago
8. The speed of the current in a river is 6 mph. A ferry operator who works that part of the river is looking to buy a new boat
Natali [406]
Answer: the speed of the boat on the lake is 9 mph
Step-by-step explanation:
Let x represent the speed of the boat on the lake or in still water.
The speed of the current in a river is 6 mph. This means that if the boat goes upstream against the speed of the current, its total speed would be (x - 6)mph. If the boat goes downstream against the speed of the current, its total speed would be (x + 6)mph.
Time = distance/ speed
Every day, his route takes him 22.5 miles each way against the current and back to his dock, and he needs to make this trip in a total of 9 hours. This means that the time taken to travel upstream is
22.5/(x - 6). The time taken to travel downstream is
22.5/(x + 6)
Since the total time is 9 hours, it means that
22.5/(x - 6) = 22.5/(x + 6)
Cross multiplying, it becomes
22.5(x + 6) + 22.5(x - 6) = 9
Multiplying through by (x + 6)(x - 6), it becomes
22.5(x - 6) + 22.5(x + 6) = 9[(x + 6)(x - 6)]
22.5x - 135 + 22.5x + 135 = 9(x² - 6x + 6x - 36)
22.5x + 22.5x = 9x² - 324
9x² - 45x - 324 = 0
Dividing through by 9, it becomes
x² - 5x - 36 = 0
x² + 4x - 9x - 36 = 0
x(x + 4) - 9(x + 4) = 0
x - 9 = 0 or x + 4 = 0
x = 9 or x = - 4
Since the speed cannot be negative, then x = 9
3 0
2 years ago
Read 2 more answers
GCF of 15x^2y^3 and -20x^3yz
nadezda [96]

15x^2y^3=3\cdot\boxed{5}\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{y}\cdot y\cdot y\\\\-20x^3yz=-2\cdot2\cdot\boxed{5}\cdot\boxed{x}\cdot\boxed{x}\cdot x\cdot\boxed{y}\cdot z\\\\GCF(15x^2y^3,\ -20x^3yz)=\boxed{5}\cdot\boxed{x}\cdot\boxed{x}\cdot\boxed{y}=5x^2y

4 0
3 years ago
Need the answers plz
Shkiper50 [21]
1)
           x^2 + 4x - 5
y =   --------------------
              3x^2 - 12

Vertcial asym => find the x-values for which the equation is not defined and check whether the limit goes to + or - infinite

=> 3x^2 - 12 = 0 => 3x^2 = 12

=> x^2 = 12 / 3 = 4

=> x = +/-2

Limit of y when x -> 2(+) = ( 2^2 + 4(2) - 5) / 0 = - 1 / 0(+) =  ∞

Limit of y when x -> 2(-) = - 1 / (0(-) = - ∞

Limit of y when x -> - 2(+) = +∞

Limit of y when x -> - 2(-) = -

=> x = 2 and x = - 2 are a vertical asymptotes

Horizontal asymptote => find whether y tends to a constant value when x -> infinite of negative infinite

Limi of y when x -> - ∞ = 1/3

Lim of y when x -> +∞ = 1/3

=> Horizontal asymptote y = 1/3

x - intercept => y = 0

=>
          x^2 + 4x - 5
0 =   ------------------ => x ^2 + 4x  - 5 = 0
              3x^2 - 12

Factor x^2 + 4x - 5 => (x + 5) (x - 1) = 0 => x = - 5 and x = 1

=> x-intercepts x = - 5 and x = 1

Domain: all the real values except x = 2 and x = - 2

2)  y = - 2 / (x - 4) - 1

using the same criteria you get:

Vertical asymptote: x = 4

Horizontal asymptote: y = - 1

Domain:all the real values except x = 4

Range: all the real values except y = - 1

3) 

x/ (x + 2) + 7 / (x - 5) = 14 / (x^2 - 3x - 10)

factor x^2 - 3x - 10 => (x - 5)(x + 2)

Multiply both sides by (x - 5) (x + 2)

=> x(x - 5) + 7( x + 2) = 14

=> x^2 - 5x + 7x + 14 = 14

=> x^2 + 2x = 0

=> x(x + 2) = 0 => x = 0 and x = - 2 but the function is not defined for x = - 2 so it is not a solution => x = 0

Answer: x = 0
4 0
3 years ago
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