Y=1/2·3^0 help show the work please? ASAP NOW jk but for real now will be a good time
1 answer:
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Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t - ) And
yB = 8 sin(2t - )
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( - +
)
Or, phase difference between yA and yB =
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is Answer