Answer:

Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:

For a uniform distribution, we have:

and

implies that:

So, we have:

Solve


Recall that:

Make x the subject

So, the cumulative density is:

becomes

The CDF is:

Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand

The density function of the volume F(v) is:

Differentiate F(x) to give:




So:

Answer:
m = (ps - b - uxs/t) / ux/t - p
Step-by-step explanation:
ux/t +b/m+s =p
multiplying throughout by (m+s) we get:
ux/t(m+s) + b = p(m+s)
open the brackets:
uxm/t + uxs/t + b = pm + ps
bring on one side of the equal sign all terms containg m, to make it the subject:
m(ux/t - p) = ps - b - uxs/t
m= (ps - b - uxs/t) / ux/t - p
Answer:
(x+6)
Step-by-step explanation:
because you have ( x+6) on bottom of the first equation and on the top on the second equation