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2 years ago

What is the slope of the line through (6,9)(6,9)left parenthesis, 6, comma, 9, right parenthesis and (7,1)(7,1)

Mathematics

2 answers:

ankoles [38]2 years ago

8 0

Answer:

y = -8x + 57

Step-by-step explanation:

hope this helps! :)

andrezito [222]2 years ago

5 0

Answer:

-8

Step-by-step explanation:

I don't really have an explenation

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Which fraction expresses 36/80 in lowest terms. A- 9/20 B-18/40 C-4/5 D- 18/20

gladu [14]

B) is the correct answer.

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3 years ago

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What is the sum of 1/10+8/100

galben [10]

$\frac{1}{10} + \frac{8}{100} = \frac{10}{100} + \frac{8}{100}= \frac{10+8}{100}=\frac{18}{100} = \frac{9}{50}$

8 0

3 years ago

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

13. Solve for m. Assume that none of the denominatons are equal to 0 Plz help me

givi [52]

Answer:

m = (ps - b - uxs/t) / ux/t - p

Step-by-step explanation:

ux/t +b/m+s =p

multiplying throughout by (m+s) we get:

ux/t(m+s) + b = p(m+s)

open the brackets:

uxm/t + uxs/t + b = pm + ps

bring on one side of the equal sign all terms containg m, to make it the subject:

m(ux/t - p) = ps - b - uxs/t

m= (ps - b - uxs/t) / ux/t - p

3 0

3 years ago

Which Factors would simplify in this expression?

kolbaska11 [484]

Answer:

(x+6)

Step-by-step explanation:

because you have ( x+6) on bottom of the first equation and on the top on the second equation

7 0

2 years ago