All categories

3 years ago

PLZ HELP ME 100 POINTS AND BRAINLEIST

Mathematics

1 answer:

Alina [70]3 years ago

8 0

Answer:

measure of angle b = 65

measure of angle a = 35

measure of angle c = 80

You might be interested in

When Jennifer purchases her house, she pays a 3% realtor commission for the $1800,000 loan amount. How much commission did Jenni

ankoles [38]

Answer:

$54,000

Step-by-step explanation:

1,800,000 - 3% =

1,746,000

1,800,000 - 1,746,000 =

54,000

Jennifer paid $54,000 commission fee

8 0

1 year ago

If the points (0, 0), (-1, 1), and (-2, 2) lie on the graph of function h, then which of the following rules could represent the

attashe74 [19]

The function is modulus cause the range of function consists of non-negative numbers with the same magnitude.so the second one is the answer

3 0

2 years ago

Read 2 more answers

The graph of a function must be linear if it has what characteristic?

pantera1 [17]

The graph of a function is linear of the graph is a straight line.

3 0

3 years ago

Read 2 more answers

You work with 3 other students on a project for science class. Your group

aleksandrvk [35]

Answer:

350 points are possible

Step-by-step explanation:

You take 329 divided by 94% or .94 to get 350.

100% of 350 is 350

To double check, 94% of 350 is 329 & 6% of 350 is 21. 329 +21 = 350

4 0

1 year ago

Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

8 0

2 years ago