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Licemer1 [7]
3 years ago
6

The rate at which velocity changes is called A)acceleration B)speed C)direction D)displacement

Mathematics
2 answers:
olganol [36]3 years ago
7 0
The answer is A. acceleration. Hope this helps:)))
PolarNik [594]3 years ago
4 0
Acceleration is the answer
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Question 6
Tamiku [17]

Answer:

C.

Step-by-step explanation

shes pulling RANDOM names. key word random, hope this helped

8 0
3 years ago
The sum of a number times 6 and 4 equals 5
Inessa [10]
5= (6+4)x
5= 10x

5= 10x           then divide by 10 to get the variable by itself      
__ ___
10   10
.5 = x                               you can use .5 or 1/2


hope this helps!
:)

3 0
3 years ago
Find the 20th term in the sequence, where the first term is -2 and the common ratio is-2.
geniusboy [140]

Answer:

Step-by-step explanation:

(1)

a1=-2

r=-2

a_{20}=(-2)(-2)^{20-1}=-2(-2)^{19}=2^{20}=1048576\\(2)\\a_{1}=1000\\r=\frac{200}{1000} =\frac{1}{5} \\a_{8}=1000(\frac{1}{5} )^{8-1}=1000(.2)^7=0.0128\\(3)\\a_{1}=2\\a_{3}=50\\a_{2}=\sqrt{2*50} =10\\r=\frac{10}{2} =5

6 0
3 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
3 years ago
Mary works in a factory and earns Rs.955 per month she saves Rs.185 per month. Find the ratio of
Kryger [21]

Answer:

A) 37:191

B)191:154

Step-by-step explanation:\

A) Mary's Savings= 185 Rs

Mary's Income= 955 Rs

Ratio = 185:955

= 185/955

=37/191                     ( INTO LOWEST TERMS )

=37:191

B) Mary's Income= 955 Rs

Mary's Expenditure= ?? = Income- Saving = 955-185= 770

Ratio= 955:770

= 955/770

= 191/154                  ( INTO LOWEST TERMS )

= 191:154

8 0
4 years ago
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