Question

The line perpendicular to y=3/4x+7 containing (3,-4)

Answer 1

Answer:

y = - $\frac{4}{3}$ x

Step-by-step explanation:

1). $y_{1}$ = $m_{1}$ $x_{1}$ + $b_{1}$  

$y_{2}$ = $m_{2}$ $x_{2}$ + $b_{2}$

$y_{1}$ ⊥ $y_{2}$  if  $m_{2}$ = - $\frac{1}{m_{1} }$

2). ( $x_{3}$ , $y_{3}$ )

y - $y_{3}$ = m( x - $x_{3}$ )

~~~~~~~~~~~~~~~~~~

y = $\frac{3}{4}$ x + 7

$m_{1}$ = $\frac{3}{4}$

$m_{2}$ = - $\frac{4}{3}$

( 3, - 4 )

y - ( - 4) = - $\frac{4}{3}$ ( x - 3 )

y + 4 = - $\frac{4}{3}$ x + 4

y = - $\frac{4}{3}$ x