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frutty [35]
3 years ago
10

The value of y varies inversely as the cube of x and y=1 when x=6. Find the value of y when x =2.

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

y=27 when x=2

Step-by-step explanation:

y varies inversely as the cube of x

y=k(1/X^3)

y=1 when x=6

y=k(1/X^3)

1=k(1/6^3)

1=k(1/216)

k=1÷1/216

K=1×216/1

k=216

find y when x=2

y=k(1/X^3)

y=216(1/2^3)

y=216(1/8)

y=216/8

y=27

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Hello from MrBillDoesMath!

Answer:

"-3" is added to a sequence member to get the next number. This next two terms are -14 and  -17


Discussion:

Note that -2 -3 = -5 and

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"-3" is added to a sequence member to get the next number. This implies that the next two terms are -11 -3 = -14 and -14 -3 = -17

Regards,  

MrB


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3 years ago
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MissTica

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