B I’m pretty sure sorry if wrong
Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
You need to know the equation of motion for the particle.
Arc length of the quarter circle is 1.57 units.
Solution:
Radius of the quarter circle = 1
Center angle (θ) = 90•
Arc length = 1.57 units
Arc length of the quarter circle is 1.57 units.
<span>1. </span><span>A penny weighs about 0.1 oz.
Now, we need to find the weights of pennies in pounds
=> always remember that in every 1 oz, there is 0.0625 pounds.
Since 0.1 is 1/10 of 1 oz, we need to find the value of it in pounds.
=> 0.0625 pounds / 10
=> 0.0625 pounds.
Therefore, in 0.1 oz of penny is
equivalent to 0.00625 pounds.
In problem like this, before determining the answer, you need to make sure that
both unit of measurements are the same. If not, then try to convert.</span>
