Question

If you weigh 665 NN on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 19.0 kmkm ? Take the mass of the sun to be msmsm_s = 1.99×1030 kgkg , the gravitational constant to be GGG = 6.67×10−11 N⋅m2/kg2N⋅m2/kg2 , and the acceleration due to gravity at the earth's surface to be ggg = 9.810 m/s2m/s2 .

Answer 1

Answer:

The weight on the neutron star is 99.69 × $10^{12}$ N.

Explanation:

Here,

weight on earth is 665 N. We can calculate the mass as :

                                                 $W_{earth}$= mg

                                           or, 665= m × 9.810

                                              ∴ m = $\frac{665}{9.810}$ = 67.68 kg

Now weight of this mass on the surface of neutron star:

                            $W_{neutron star}$ = $\frac{GMm}{R^{2} }$

                                                = $\frac{(6.674*10^{-11})(1.99*10^{30})(67.68) }{9500^{2} }$

                                                = 99.69 × $10^{12}$ N

The required weight is 99.69 × $10^{12}$ N.