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Degger [83]
3 years ago
6

Diamond has a high index of refraction at about 2.4, which helps account for its sparkle. How fast does light travel through a d

ia- mond? The speed of light in a vacuum is 3 × 108 m/s. Answer in units of m/s.
Physics
1 answer:
wariber [46]3 years ago
6 0

Answer:

1.25 \cdot 10^8 m/s

Explanation:

The speed of light through a medium is given by:

v=\frac{c}{n}

where

c = 3 \cdot 10^8 m/s is the speed of light through vacuum

n is the index of refraction of the material

In this case, diamond has a refractive index of n = 2.4, so the speed of light in diamond is

v=\frac{3\cdot 10^8 m/s}{2.4}=1.25\cdot 10^8 m/s

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Assuming the incline to be frictionless and the zero of gravitational potential energy to be at the elevation of the horizontal
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The energy in the system is given by the law of conservation of energy.

The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h.

Reason:

The given parameters are;

Surface of the inclined plane = Frictionless

Potential energy at the horizontal line = Zero of gravitational potential

By the law of Conservation of Energy, we have;

The spring will be compressed by a distance, <em>x</em>

The energy stored in the compressed spring, K.E. = (1/2)·k·x²

Energy in the block when the block comes to rest at a height, h₁, will be, P.E. = m·g·h₁

Therefore, by conservation of energy, we have;

The initial potential of the block = The stored energy in the compressed string + The gravitational potential energy of the block when it has compressed.

Therefore, the correct option is; <u>The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h</u>

Learn more here;

brainly.com/question/17713698

4 0
2 years ago
A basketball player does 2.43 x 105 J of work during her time in the game, and evaporates 0,1 '10 kg of water. Assuming a latent
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The change in the player's internal energy is -491.6 kJ. The number of nutritional calories is -117.44 kCal

For this process to take place, some of the basketball player's perspiration must escape from the skin. This is because sweating relies on a physical phenomenon known as the heat of vaporization.

The heat of vaporization refers to the amount of heat required to convert 1g of a liquid into a vapor without causing the liquid's temperature to increase.

From the given information,

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The amount of heat loss is represented by dQ.

where;

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∴

Using the first law of thermodynamics:b

dU = dQ - dW

dU = -mL - dW

dU = -(0.110 kg × 2.26 × 10⁶ J/kg - 2.43 × 10⁵ J)

dU = -491.6 × 10³ J

dU = -491.6 kJ

The number of nutritional calories the player has converted to work and heat can be determined by using the relation:

\mathbf{dU = -491.6 \ kJ \times (\dfrac{1 \ cal}{ 4.186 \ J})}

dU = -117.44 kcal

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5 0
2 years ago
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Y_Kistochka [10]

Answer:

Ro = 8.65 [g/cm³]

Explanation:

We must remember that density is defined as the ratio of mass to volume.

Ro=m/V

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Ro = density [g/cm³]

Now replacing:

Ro = 450/52\\Ro = 8.65 [g/cm^{3} ]

8 0
3 years ago
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