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Natali5045456 [20]
3 years ago
10

Help again please it's math i'll make you brainliest whoever answers first!!!!!!!!!

Mathematics
1 answer:
MrMuchimi3 years ago
8 0

answer is A, if its not A then B

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Help ASAP!!
Doss [256]

Answer: 98 yards

Step-by-step explanation:

In order to find the area of a square by the diagonal, all you need to do is square the length of the diagonal and then divide by 2. 7 is half of the length, so the full length is 14. 14 squared is 196. 196 divided by 2 is 98, which is your answer.

8 0
3 years ago
Write 3x = 66 as a logarithmic function.
Musya8 [376]
Log(3) + log(x)=log(66)
log(x)=log(66)-log(3)
log(x)=log(66/3)
log(x)=log(22)
x=22
7 0
3 years ago
Read 2 more answers
4x+2=5x-1<br> Find solution to the equation
Solnce55 [7]

Answer:

3

Step-by-step explanation:

4x+2=5x-1

4x - 5x = -1 -2

x = 3

5 0
2 years ago
(Sec. 2.3) A restaurant having a grand opening is allowing visitors to try 6 different free samples from a selection. Options fo
Akimi4 [234]

Answer:A)35choices

B)475,020choices

C)132choices

D)0.000278

E)0.000166

Step-by-step explanation:

Given 7poultry items represented by 7p

10 red meat items=10R

12 vegetarian items=12V

@

A)there are 7combination 3ways of selecting 3out of 7 poultry items

From the formula nCr=n!/(n-r)!r!

7C3=7!/(7-3)!3!=7!/4!×3!=35choices

b)total items available=7p+10R+12V(denotation explained above)=29items

Choosing 6items implies

29C6=29!/(29-6)!×6!

29!/23!×6!=475,020 ways

C)7C2+10C2+12C2

7!/5!2!+10!/8!2!+12!/10!2!

21+45+66=132 choices

D) probability (choosing 2items from each class)=

7C2+10C2+12C2/29C6

Where 29C6 represent total probable.

21+45+66/29!/23!6!

=132/475020=0.000278choices

E)for meats to be in the majority on a 6choices selection impliee that vegetarian items will be

0,1 or2i.e combination of vegetarian and meat will be(0,6)or(1,5)or(2,4) .

Prob(0veg)+prob(1veg item) or prob(2veg items)

12C0+12C1+12C2/29C6

=1+12+66/475,020

=0.000166

5 0
3 years ago
The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 15
stepladder [879]
There are 2 unknown terms in this problem 
the amount of cement the first team received is termed as 'x' hereafter 
the cement the second team received is termed as 'y'
the first team received 50 kg less, the 1st equation is as follows;

x = y - 50    after rearranging 
1) x-y = -50
for every hour 150 kg and 200 kg were used by the two teams separately 
after three hours first team used up 150*3 = 450 kg
the second team used up 200 * 3 = 600 kg
however the first team had 1.5 times as much as second team had after three hours. 
After three hours;
the amount second team had leftover was y - 600
the amount first team had leftover was x - 450
 the amount the second team had ,multiplied by 1.5 is equal to what the first team had
we can build the 2nd equation using this information

1.5 * (y-600) = x-450
1.5y - 900 = x - 450 
rearrange the equation,
 
 1.5y - x = -450 +900
2) 1.5y - x = 450 

add 1st and 2nd equations to eliminate x 
1) + 2)     (x - y = -50) + (1.5y - x = 450)
1.5y - y = 450 -50
0.5y = 400
y = 400/ 0.5
y = 800 kg
substitute y = 800 in x = y - 50
x = 800 - 50 
x = 750 kg

first team received 750 kg and second team received 800 kg


8 0
3 years ago
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