Pythagorean therom HELPOP
2 answers:
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(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
![\sqrt[3]{(3x+4)^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%283x%2B4%29%5E3%7D%20)
= ![\sqrt[3]{2197}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2197%7D%20)
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3
3 and 3 cancels out
x = 3
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3
3 and 3 cancels out
x = 3