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shusha [124]
3 years ago
11

Pythagorean therom HELPOP

Mathematics
2 answers:
Oliga [24]3 years ago
4 0

Answer:

its 12

Step-by-step explanation:

Lemur [1.5K]3 years ago
3 0
The width of the pond is 12
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A field has a length of 6 2/3 yards and a width of 4 3/4 yards. What is the area of the field.
gulaghasi [49]

Answer:

Ste-by-step explanation:

That doesn’t answer it stupid

6 0
3 years ago
In a car how many miles do you go per day? How many days until you hit 10,000 miles?
cricket20 [7]
I drive 25 miles per day

divide the number of miles per day by the total miles to find how long it will take:

10,000 miles / 25 miles per day = 400 days


6 0
3 years ago
Read 2 more answers
Perfect square between 1 and 9
Rasek [7]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
How far from an airport can an airplane fly and return in 8 hours, if it's outgoing speed is 160 km per hour and it's returning
PilotLPTM [1.2K]
<span>speed = distance/time
total time is 8 hours

outgoing speed is 160 km per hour, 
so time = d/160

</span><span>returning speed is 240 km per hour,
so time = d/240

 d/160 + d/240 = 8

3d/480 + 2d/480 = 8
5d/480 = 8
5d =480 (8)
5d = 3840
d=3840/5
d=768

answer: so the distance is 768 km</span>
4 0
3 years ago
Read 2 more answers
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
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