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marysya [2.9K]
3 years ago
5

Rowanda jogged 2.17 kilometers farther than Terrance. Select the values that could represent how far each student jogged. Select

all that apply.
A Rowanda: 6.8 km, Terrance: 4.63 km
B Rowanda: 4.5 km, Terrance: 2.43 km
C Rowanda: 7.23 km, Terrance: 5.06 km
D Rowanda: 3.52 km, Terrance: 1.45 km
Mathematics
1 answer:
Simora [160]3 years ago
7 0

Answer:

A and C

Step-by-step explanation:

6.8 - 2.17 = 4.63

7.23 - 2.17 = 5.06

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On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
VladimirAG [237]

Answer:

a) 2\frac{7}{12} kg of plant food did Sheldon have left.

b) She need is \frac{43}{12} kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought 4\frac{1}{2} kg of plant food. He used 1\frac{2}{3} kg on his strawberry plants and used \frac{1}{4} kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food 4\frac{1}{2}=\frac{9}{2} kg.

He used strawberry plants 1\frac{2}{3}=\frac{5}{3} kg.

He used tomato plants \frac{1}{4} kg

Kilograms of plant food did Sheldon have left is given by,

L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})

L=\frac{9}{2}-\frac{23}{12}

L=\frac{54-23}{12}

L=\frac{31}{12}

L=2\frac{7}{12}

Therefore, 2\frac{7}{12} kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is 2(\frac{5}{3})=\frac{10}{3} kg.

His tomato plants one more time i.e. \frac{1}{4} kg.

Total plant she need is \frac{10}{3}+\frac{1}{4}=\frac{43}{12}

As \frac{31}{12}

No she don't have enough to left.

4 0
3 years ago
Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +
nevsk [136]

Answer:

x_2 \approx -1.769

Step-by-step explanation:

Let f(x)=x^3+x+7

So f'(x)=3x^2+1

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

Let x_1=-2

We are going to find x_2

So we are evaluating -2-\frac{f(-2)}{f'(-2)}

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3

f'(-2)=3(-2)^2+1=3(4)+1=12+1=13

So

x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769

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2 years ago
71 to the nearest tenth
xeze [42]

Answer:

ft76d956

Step-by-step explanation:

6 0
3 years ago
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Alex787 [66]

Answer:

Acute angle.

Right angle.

Obtuse angle.

Straight angle.

Reflex angle

Step-by-step explanation:

4 0
3 years ago
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Is 6/6 more than 3/3
hodyreva [135]
They are both equivalent to 1, so they are equal. 

4 0
3 years ago
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