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3 years ago

5

Paul and tested twice as much money in an account paying 7% interest then he did an account paying 2% interest if the total inte

rest paid less $240 how much did he invest in each

1 answer:

geniusboy [140]3 years ago

7 0

I think this is correct 14% interest and 4% interest

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3241004551 [841]

Answer:

" $e^x$ is irrational for every nonzero integer x"

Step-by-step explanation:

The original statement is

" $e^x$ is rational for some nonzero integer x."

The negation is technically:

"It is NOT true that $e^x$ is rational for some nonzero integer x."

So it's expressing that it's false that $e^x$ can be rational for some nonzero integer x.

This just means that $e^x$ is always irrational when x is a nonzero integer.

Which can be worded as

" $e^x$ is irrational for every nonzero integer x"

4 0

3 years ago

A mountain climber descends 3,852 feet over a period of 4 days. What was the average amount of her descent over that period of t

Harrizon [31]

To get the answer, divide 3852 feet by 4 days. That will give you an average of 963 feet per day as your answer.

5 0

3 years ago

Read 2 more answers

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

Twice as many students are in the chess club as in the fencing club.The number of students in the fencing club is one fifth the

jekas [21]

Answer:

28 students

Step-by-step explanation:

Let number of students in cooking club = x

Number of students in fencing club = 1/5 x

Number of students in chess club = 2(1/5)x

Since, There are 42 more students in the cooking club than in the chess club

Then ;

Number of students in chess club = Number of students in cooking club - 42

2(1/5)x = x - 42

(2/5)x - x = - 42

(2/5)x - x = - 42

-0.6x = - 42

x = 42 / 0.6

x = 70

Hence, number of students in chess club :

(2/5) * 70 = 28

4 0

3 years ago

Write the next three terms of the following sequence 4,5,7,10,14

Law Incorporation [45]

4,5,7,10,14=19,25, 32

8 0

3 years ago