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TiliK225 [7]
3 years ago
12

What does the equation x^2+y^2=14 represent?

Mathematics
1 answer:
sdas [7]3 years ago
8 0
Your answer is b. circle 
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What is the length of the arc on a circle with radius 20 in. intercepted by a 15° angle? Use 3.14 for π . Round the answer to th
Fofino [41]
We know, length of arc = Ф/360 * 2πr
= 15/360 * (2 * 3.14 * 20)
= 1/24 * (125.6)
= 5.23

In short, Your Answer would be 5.23 Inches

Hope this helps!
5 0
3 years ago
Solve for x x-4=-7. Please
Alecsey [184]

Answer:

-3

Step-by-step explanation:

x - 4 = - 7

Carry over the - 4 and make x the subject.

x= - 7 + 4

x= - 3

Therefore x is - 3

8 0
3 years ago
Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu
Alisiya [41]
Let y=C_1x+C_2x^3=C_1y_1+C_2y_2. Then y_1 and y_2 are two fundamental, linearly independent solution that satisfy

f(x,y_1,{y_1}',{y_1}'')=0
f(x,y_2,{y_2}',{y_2}'')=0

Note that {y_1}'=1, so that x{y_1}'-y_1=0. Adding y'' doesn't change this, since {y_1}''=0.

So if we suppose

f(x,y,y',y'')=y''+xy'-y=0

then substituting y=y_2 would give

6x+x(3x^2)-x^3=6x+2x^3\neq0

To make sure everything cancels out, multiply the second degree term by -\dfrac{x^2}3, so that

f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y

Then if y=y_1+y_2, we get

-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0

as desired. So one possible ODE would be

-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0

(See "Euler-Cauchy equation" for more info)
6 0
3 years ago
Maria told Patrick that her quarter weighs less than what a nickel weighs because 0.2 has fewer digits than .18. How can Patrick
Dimas [21]
If you add a zero at the end it is easier to understand. 0.20 > 0.18 because 20 is greater than 18
6 0
3 years ago
What is the answer? 3rd time posting. <br> Worth 15 points.<br> Explain
Gekata [30.6K]
KCC
7 units 7-4=3 (-9)-(-5)=
-9+5=(-4)
3+(-4)= 7
4 0
3 years ago
Read 2 more answers
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