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3 years ago

What does the equation x^2+y^2=14 represent?

Mathematics

1 answer:

sdas [7]3 years ago

8 0

Your answer is b. circle

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What is the length of the arc on a circle with radius 20 in. intercepted by a 15° angle? Use 3.14 for π . Round the answer to th

Fofino [41]

We know, length of arc = Ф/360 * 2πr
= 15/360 * (2 * 3.14 * 20)
= 1/24 * (125.6)
= 5.23

In short, Your Answer would be 5.23 Inches

Hope this helps!

5 0

3 years ago

Solve for x x-4=-7. Please

Alecsey [184]

Answer:

-3

Step-by-step explanation:

x - 4 = - 7

Carry over the - 4 and make x the subject.

x= - 7 + 4

x= - 3

Therefore x is - 3

8 0

3 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

Maria told Patrick that her quarter weighs less than what a nickel weighs because 0.2 has fewer digits than .18. How can Patrick

Dimas [21]

If you add a zero at the end it is easier to understand. 0.20 > 0.18 because 20 is greater than 18

6 0

3 years ago

What is the answer? 3rd time posting. <br> Worth 15 points.<br> Explain

Gekata [30.6K]

KCC
7 units 7-4=3 (-9)-(-5)=
-9+5=(-4)
3+(-4)= 7

4 0

3 years ago

Read 2 more answers