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Triss [41]
3 years ago
15

Quesuon 2

Mathematics
1 answer:
Reil [10]3 years ago
5 0

The volume of the box is 48 m^3

Step-by-step explanation:

Let V_u be the volume of unit cube with side b

So,

V_u = b^3\\V_u = 1^3\\V_u = 1\ m^3

As it is given that the box can be packed with 48 unit cubes which means that 48 unit cubes will ft in the box.

The induces that the volume of 48 unit cubes will be the volume of the box.

Let V_b be the volume of the box

So

V_b = 48V_u\\V_b = 48 * 1\\V_b = 48\ m^3

Hence,

The volume of the box is 48 m^3

Keywords: Volume, units

Learn more about volume at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume)
timofeeve [1]

If the density of the man is 1.0321 grams per cubic cm. Then the body fat percentage will be 28.59%.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume) and apply a formula to convert it to a body fat percentage.

\rm BF = \left (\dfrac{4.57}{p} - 4.142 \right) \times 100

where BF = body fat and p = density in g/cm3 A man weighs 175 pounds.

A man weighs 175 pounds.

His total body volume is modeled by a cylinder with a height of 170 cm and a radius of 12 cm.

Then the density will be

\rm p = \dfrac{175 \times 453.592}{\pi \times 12^2 \times 170}\\\\p = \dfrac{79378.7}{76906.19}\\\\p= 1.0321 \ g/cm^3

Then the Body fat percentage will be

\rm BF = \left (\dfrac{4.57}{1.0321} - 4.142 \right) \times 100 \\\\\\BF = 0.2859 \times 100\\\\\\BF = 28.59\%

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

8 0
2 years ago
Approximate the unit price of a 10 ounce bottle of ketchup that sells for $1.59.
andreev551 [17]
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Iodine-131 has a half-life of 8 days. How much would be left of an original 40 g sample after 40 days?
Yuri [45]

Answer:

d) 1.25 g

Step-by-step explanation:

If it has a half life of 40 days, there will be 5 half-lives in that span of time so if you divide 40 by 2, 5 times or just \frac{40}{2^{5} }, it will equal 1.25.

\frac{40}{2}=20\\

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A classroom had 35 glue sticks. If the ratio of glue sticks to glue bottles was 5:2, how many glue bottles did the classroom hav
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There would be 12 glue bottles in the classroom. Hope this helps you!

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