Question

An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume) and apply a formula to convert to a body fat percentage. Formula: BF = (4.57/p - 4.142) x 100 where BF = body fat and p = density in g/cm3 A man weighs 175 pounds. His total body volume is modeled by a cylinder with a height of 170 cm and a radius of 12 cm. Find his body fat percentage, based upon the given formula (to the nearest percent).

Answer 1

If the density of the man is 1.0321 grams per cubic cm. Then the body fat percentage will be 28.59%.

What is a function?

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

An older method of estimating body fat percentage was to measure a person's average density (total mass divided by total volume) and apply a formula to convert it to a body fat percentage.

$\rm BF = \left (\dfrac{4.57}{p} - 4.142 \right) \times 100$

where BF = body fat and p = density in g/cm3 A man weighs 175 pounds.

A man weighs 175 pounds.

His total body volume is modeled by a cylinder with a height of 170 cm and a radius of 12 cm.

Then the density will be

$\rm p = \dfrac{175 \times 453.592}{\pi \times 12^2 \times 170}\\\\p = \dfrac{79378.7}{76906.19}\\\\p= 1.0321 \ g/cm^3$

Then the Body fat percentage will be

$\rm BF = \left (\dfrac{4.57}{1.0321} - 4.142 \right) \times 100 \\\\\\BF = 0.2859 \times 100\\\\\\BF = 28.59\%$

More about the function link is given below.

brainly.com/question/5245372

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