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dlinn [17]
3 years ago
8

A classroom had 35 glue sticks. If the ratio of glue sticks to glue bottles was 5:2, how many glue bottles did the classroom hav

e
Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

There would be 12 glue bottles in the classroom. Hope this helps you!

agasfer [191]3 years ago
3 0

Answer:

14 glue bottles

Step-by-step explanation:

35 divided by 5 is 7 and 7 times 2 is 14

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A diver dives from the board at a local swimming pool. Her height, y, in metres, above the water in terms of her horizontal dist
Aneli [31]

Answer:

4 meters

Step-by-step explanation:

Given a quadratic equation in which the coefficient of x^2 is negative, the parabola opens up and has a maximum point. This maximum point occurs at the line of symmetry.

Since the divers height, y is modeled by the equation

y= -x^2 + 2x + 3

Step 1: Determine the equation of symmetry

In the equation above, a=-1, b=2, c=3

Equation of symmetry, x=-\dfrac{b}{2a}

x=-\dfrac{2}{2*-1}\\x=1

Step 2: Find the value of y at the point of symmetry

That is, we substitute x obtained above into the y and solve.

y(1)= -1^2 + 2(1) + 3=-1+2+3=4m

The maximum height of the diver is therefore 4 meters.

8 0
3 years ago
Please help me out !
Ahat [919]

Answer:

a) -9/-10 (4th)

b) -3/5 (4th)

3 0
3 years ago
Read 2 more answers
What’s 4/5 times 7/8
kotykmax [81]
68 because I found out on internet
7 0
3 years ago
Read 2 more answers
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that t
Inga [223]

Answer:

f(2n)-f(n)=log2

b.lg(lg2+lgn)-lglgn

c. f(2n)/f(n)=2

d.2nlg2+nlgn

e.f(2n)/(n)=4

f.f(2n)/f(n)=8

g. f(2n)/f(n)=2

Step-by-step explanation:

What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]

from a

f(n)=logn

f(2n)=lg(2n)

f(2n)-f(n)=log2n-logn

lo(2*n)=lg2+lgn-lgn

f(2n)-f(n)=lg2+lgn-lgn

f(2n)-f(n)=log2

2.f(n)=lglgn

F(2n)=lglg2n

f(2n)-f(n)=lglg2n-lglgn

lg2n=lg2+lgn

lg(lg2+lgn)-lglgn

3.f(n)=100n

f(2n)=100(2n)

f(2n)/f(n)=200n/100n

f(2n)/f(n)=2

the time will double

4.f(n)=nlgn

f(2n)=2nlg2n

f(2n)-f(n)=2nlg2n-nlgn

f(2n)-f(n)=2n(lg2+lgn)-nlgn

2nLg2+2nlgn-nlgn

2nlg2+nlgn

5.we shall look for the ratio

f(n)=n^2

f(2n)=2n^2

f(2n)/(n)=2n^2/n^2

f(2n)/(n)=4n^2/n^2

f(2n)/(n)=4

the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare

6.n^3

f(n)=n^3

f(2n)=(2n)^3

f(2n)/f(n)=(2n)^3/n^3

f(2n)/f(n)=8

the ratio will be times 8 the initial

7.2n

f(n)=2n

f(2n)=2(2n)

f(2n)/f(n)=2(2n)/2n

f(2n)/f(n)=2

5 0
3 years ago
Suppose the scientist performs an experiment in which she cools the three gases. Will the changes in temperature be positive or
yaroslaw [1]
In the case that a scientist cools three gases in an experiment, the change in temperature will be negative for the experiment. This is because cooling results in a temperature lower than the original temperature. For example, a gas originally at 25°C when cooled to 20°C has a temperature change of -5°C. 
8 0
3 years ago
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