Answer:
Part 1)
Bob's mistake was to have used the cosine instead of the sine
The measure of the missing angle is 
Part 2) The surface area of the pyramid is 
Step-by-step explanation:
Part 1)
Let
x----> the missing angle
we know that
In the right triangle o the figure
The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle


Bob's mistake was to have used the cosine instead of the sine
Part 2) we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
where
b is the length side of the square
h is the height of the triangular lateral face
In this problem
-------> by an 45° angle
so



Find the value of b

Find the surface area
![SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}](https://tex.z-dn.net/?f=SA%3D12%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2812%29%286%29%5D%3D288%5C%20cm%5E%7B2%7D)
4=5x-16 is your answer and when you take the 3x from the left side then you also have to take it from the 8x on the other side
Answer: 13/12
Step-by-step explanation:
Common denominator:12
9/12 plus 4/12 equals 13/12 equals 1 1/12
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
Part 1) Find the measure of angle ECF
we know that
CF is tangent at point C
so
the radius EC is perpendicular to the tangent CF
therefore

Part 2) Find the measure of angle AKB
we know that
The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite

substitute the values

Part 3) Find the measure of angle ACF
we know that
The inscribed angle is half that of the arc it comprises

substitute the values
