I believe the answer is hypothesis since the conclusion is after everything and the test is the experiment
The distance of the object from the mirror is 3cm.
To calculate the distance of the object from the mirror, we make use of the mirror formula
<h3>Mirror formula</h3>
- 1/f = (1/u)+(1/v)............ Equation 1
Where:
- f = Focal length of the mirror
- v = image distance
- u = object distance.
Using the real is positive convention,
Given:
Substitute these values into equation 1 and solve for u
- 1/5 = (-1/10)+(1/u)
- 1/5+(1/10) = 1/u
- 1/u = (2+1)/10
- 1/u = 3/10
- u = 10/3
- u = 3.33
- u = 3 cm
Hence, The distance of the object from the mirror is 3cm.
Learn more about mirror formula here: brainly.com/question/26257987
Firstly simplify both sides
using distributive terms
(-8)(2)+(-8)(-3w)+-5w
=-16+24w+-5w
combine like terms
-16+24w+-5w
=(24w+5w)+(-16)
=19w+-16
the answer is 19w+ -16
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2. The area of the unshaded square in Figure 1 can be represented by . The combined area of the two unshaded squares in Figure 2 can be represented by . The areas of the squares in Figure 1 and Figure 2 show that .
Given :
Figure 1 and figure 2 are given.
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2.
The area of the unshaded square in Figure 1 can be represented by .
The combined area of the two unshaded squares in Figure 2 can be represented by .
The areas of the squares in Figure 1 and Figure 2 show that .
