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Black_prince [1.1K]
3 years ago
5

Bianca has a total of $0.25 she has some nickels and pennies how many different combinations of nickels and pennies could Bianca

have make a table to solve it
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0
4 nickels and 5 pennies. 
5 nickels and 0 pennies
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What is the x intercept of y + 4 =− 4(x − 1)
vivado [14]

Answer:

0

Step-by-step explanation:

since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.

7 0
2 years ago
Which link between two elements could you remove from the relation so that it becomes a function? 1 and c or 3 and a 4 and d or
shtirl [24]
It would make more sense to remove 4 and D

8 0
3 years ago
Read 2 more answers
In the figure below, AMNO
NeX [460]

Given:

\Delta MNO\cong \Delta PQR

To find:

The length of QR.

Solution:

We have,

\Delta MNO\cong \Delta PQR

Then, MN=PQ                 (CPCTC)

10=4x-2

10+2=4x

12=4x

Divide both sides by 4.

\dfrac{12}{4}=x

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Similarity,

MO=PR            (CPCTC)

2y+3=21

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y=9

Now,

x+y=3+9

x+y=12

Therefore, the correct option is d.

4 0
3 years ago
"how many different rectangles" can you draw that have a perimeter of 12, 14
amm1812
Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width





3 0
3 years ago
Please solve with explanation 20 points
VashaNatasha [74]

Answer: i don't know but thanks for the points

Step-by-step explanation:

4 0
2 years ago
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