Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer:
Step-by-step explanation:
<u>Given </u>
<u>In the first quadrant both sine and cosine are positive, so as tangent.</u>
- tanθ = sinθ / cosθ =
θ / cosθ = 
/ 4/5 = 
/ 4/5 = - 3/5*5/4 =
- 3/4
The decimal equivalent to 5/8 is .625
Answer: Choice A) 32
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Plug n = 4 into the formula
tn = 4(2)^(n-1)
t4 = 4(2)^(4-1) ... every n is replaced with 4
t4 = 4(2)^3
t4 = 4(8)
t4 = 32
Answer and Step-by-step explanation:
To find the length of the missing leg, use the Pythagorean Theorem.
<u>This missing leg length is 8 feet.</u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
