The formula of the line is
y=mx + b
The likes goes through the point (0,0)
that means that y-int = 0, b=0
y=mx
So we need to find only slope.
RemarkIf you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step OneDivide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step TwoDifferentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =
Frankly I like the first answer better, but you have a choice of both.
Answer:
Step-by-step explanation:
First, make sure you know which section of the number line you want as 1 and 2. Next, put 0.25 not right at 0 but very close, then put 0.75 farther but not too much from 0.25. Then for the decimal 1.99 put that very close to where you marked the 2 but, not on the 2. Finally, put 2.03 very close to 2 but not exactly on the 2. Also, make sure that the number line is marked evenly.
A. cause i did it on the calculator so i know its right
