Question

If a line crosses the y-axis at (0,-3) and has a slope of 3, what is the equation of the line?

Answer 1

Okay so first you need to put it into point slope form which is y - y1=m(x-x1)

So y + 3 = 3 ( x - 0)
y+3 = 3x - 0

then carry the 3 over.

y= 3x - 0 - 3

y= 3x -3 is your answer.

Answer 2

Y=mx+b
m=slope
b=y intercept (take the point and take the y value and input it for b)

crosses y axis=y intercept=(0,-3), b=-3
slope=3
y=3x-3