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Vladimir [108]
3 years ago
8

Suraji took a slice of pizza from the freezer and put it in the oven. The pizza’s temperature (in degrees Celsius) as a function

of time (in minutes) is graphed. How long was each increase by 4 degrees Celsius?
A. 1/4 minute
B. 1/2 minute
C. 1/3 minute
D. 1 minute

Mathematics
2 answers:
anygoal [31]3 years ago
7 0

Answer:

b.1/2 minute

Step-by-step explanation:

Brilliant_brown [7]3 years ago
3 0

Answer:

b

Step-by-step explanation:

im not sure

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An athlete takes 10 rounds of a rectangular park, 60 m long and 35 m wide. Find the total distance covered by him
serious [3.7K]

Answer:

1900M

Step-by-step explanation:

If the athlete runs round a rectangular park, the distance covered can be determined by calculating the perimeter of the park

Perimeter of a rectangle = 2 x (length + width)

2 x (60 + 35) = 190m

Since he run rounds 10 times, the total distance covered = 190m x 10 = 1900m

5 0
3 years ago
I need help with this as well I can not get it right!
stepan [7]
41.5





Just enter it in a calculator
8 0
3 years ago
Read 2 more answers
Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re
mixer [17]

Answer: range= 26, variance= 80 and standard deviation= 8.94

Step-by-step explanation:

Range = highest - lowest

Range = 146 - 120

Range= 26

Let m be mean

M=mean=sum/n

Mean=(120+134+146+127+138+133) / 6

M=798/6

M=133

The standard deviation sample formula:

S.D = sqrt( Summation of |x-m|^2 / n-1)

Let start finding:

|x-m|^2

For 1st: |120-133|^2=169

For 2nd: |134-133|^2=1

For 3rd: |146-133|^2=169

For 4th: |127-133|^2=36

For 5th: |138-133|^2=25

For 6th: |133-133|^2=0

Summation of |x-m|^2 = 400

The standard deviation formula is :

S.D = sqrt( Summation of |x-m|^2 / n-1)

S.D= sqrt(400 / 5)

S.D=sqrt(80)

S.D= 8.94

Variance = (Summation of |x-m|^2 / n-1)

Variance= 400/5

Variance= 80

3 0
3 years ago
Read 2 more answers
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
What is 7539 increased by 3200
Tanya [424]
Subtract thats how you get it
5 0
3 years ago
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