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weqwewe [10]
4 years ago
6

The pen is supposed to be 42.6 feet long and 28.5 feet wide. How many feet of chicken coop wire are needed to form the pen?

Mathematics
2 answers:
VikaD [51]4 years ago
3 0
Approximately 150 ft
Nastasia [14]4 years ago
3 0

142.2 feet of wire are needed to form the pen. To solve you must find the perimeter. You do this by multiplying the length and width by two then adding them together. You could also use the equation: l2+w2

l = length

w = width

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Help ASAP ................
olya-2409 [2.1K]

Answer:

30-17=13 pounds that's the answer

6 0
3 years ago
Read 2 more answers
Find the sum (x^3+5x^2+3x-7)+(8x-6^2+6) <br> Find the difference (7x-3x^2+2)-(x^3+5x^2+2x-5)
KATRIN_1 [288]

Answer:

x^3 - x^2 + 11x - 1

-x^3 - 8x^2 + 5x + 7

Step-by-step explanation:

Find the sum

(x^3+5x^2+3x-7)+(8x-6x^2+6)

=x^3+5x^2+3x-7+8x-6x^+6

Collect like terms

=x^3 +5x^2-6x^2+3x+8x-7+6

Add the like terms

= x^3 - x^2 + 11x - 1

Find the difference (7x-3x^2+2)-(x^3+5x^2+2x-5)

(7x-3x^2+2)-(x^3+5x^2+2x-5)

= 7x-3x^2+2-x^3-5x^2-2x+5

Collect like terms

= -x^3-3x^2-5x^2+7x-2x+2+5

Add the like terms

= -x^3 - 8x^2 + 5x + 7

5 0
3 years ago
3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3)<br> How to solve pls?
babunello [35]

Answer:

3(4 {x}^{2}  {y}^{3} + 2 {x}^{3}) - 4(9 {x}^{3}  {y}^{2}  - 6 {x}^{2}  {y}^{3} ) \\  = (12 {x}^{2}  {y}^{3}  + 6 {x}^{3} ) - (36{x}^{3}  {y}^{2} - 24{x}^{2}  {y}^{3}) \\  = (12 {x}^{2}  {y}^{3}  + 6 {x}^{3} )  +  ( - 36{x}^{3}  {y}^{2}  +  24{x}^{2}  {y}^{3}) \\  = - 36{x}^{3}  {y}^{2}  + 36x^{2}  {y}^{3} + 6 {x}^{3}

I hope I helped you^_^

4 0
3 years ago
The answer plzzzzzzzzzzzzzzzzzzzzzz
Tanzania [10]

Answer: (3) y= 2x+8

Step-by-step explanation:

6 0
3 years ago
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If sin 0 =<br> 6<br> 12<br> find cos 0 and sin 8.
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