Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
- 4x + 3y = 12 ( add 4x to both sides )
3y = 4x + 12 ( divide the terms by 3 )
y =
x + 4 ← in slope- intercept form
with slope m =
and y- intercept c = 4
---------------------------------------------------
Given
- 5x + 3y = - 9 ( add 5x to both sides )
3y = 5x - 9 ( divide the terms by 3 )
y =
x - 3 ← in slope- intercept form
with slope m =
and y- intercept c = - 3
Sqrt(9)÷25= 0.12 I hope this helps!
68%. There is a 17% faliure rate for a computer, so if you buy 4 computers...
17 x 4 = 68%
Correct me if Im wrong!
The average time the car took to reach each checkpoint are:
<h3>Average time</h3>
Given:
Time interval
1 2 3 4
2.02 3.17 4.12 4.93
2.05 3.07 3.98 4.81
2.15 3.25 4.23 5.01
Hence:
First quarter checkpoint
Average time= (2.02 + 2.05 + 2.15) / 3
Average time=6.22/3
Average time= 2.07s
Second quarter checkpoint
Average time= (3.17 +3.07 + 3.25) / 3
Average time=9.49/3
Average time = 3.16 s
Third quarter check point
Average time= (4.12 + 3.98 + 4.23) / 3
Average time=12.33/3
Average time= 4.11 s
Fourth quarter check point
Average time = (4.93 + 4.81 + 5.01) / 3
Average time=14.75/3
Average time= 4.917 s
Average time=4.92s (Approximately)
Therefore the average time the car took to reach each checkpoint are: 2.07, 3.16, 4.11, 4.92.
Learn more about average time here:brainly.com/question/19136062
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