Answer:
Step-by-step Explanation:
![\huge \frac{2 + \sqrt[3]{3} }{ \sqrt[3]{6} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6} \times \sqrt[3]{6} }{\sqrt[3]{6} \times \sqrt[3]{6}} \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6 ^{2} } }{\sqrt[3]{6^{2}} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }} \\ \\ = \huge \frac{(2 \sqrt[3]{6} + \sqrt[3]{3} \sqrt[3]{6} )}{ \sqrt[3]{6 ^{3} }} \\ \\ = \huge \orange{\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cfrac%7B2%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%20%20%7D%7B%5Csqrt%5B3%5D%7B6%5E%7B2%7D%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%5Csqrt%5B3%5D%7B6%7D%20%29%7D%7B%20%20%5Csqrt%5B3%5D%7B6%20%5E%7B3%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%20%5Corange%7B%5Cfrac%7B2%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B18%7D%20%7D%7B%20%206%7D%20%20%7D)
Answer:
try Jiskha Homework Help
Step-by-step explanation:
Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴ 
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180

Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°
Answer:
She gets an increase of $750 each year so in the tenth year she would make $34,850
Step-by-step explanation: